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10th Maths Solutions Chapter 3 Algebra Ex 3.5

  Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.5

10th Maths Exercise 3.5 Samacheer Kalvi Question 1.
Simplify
10th Maths Exercise 3.5 Samacheer Kalvi Chapter 3 Algebra
Solution:
Ex 3.5 Class 10 Samacheer Kalvi Chapter 3 Algebra

Ex 3.5 Class 10 Samacheer Question 2.
Simplify
10th Maths Exercise 3.5 Samacheer Kalvi Chapter 3 Algebra
Solution:
10th Maths Exercise 3.5 Samacheer Kalvi Chapter 3 Algebra
Exercise 3.5 Class 10 Maths Samacheer Kalvi Chapter 3 Algebra

10th Maths Exercise 3.5 Samacheer Question 3.
Simplify
10th Maths 3.5 Samacheer Kalvi Chapter 3 Algebra
Solution:
10th Maths Ex 3.5 Samacheer Kalvi Chapter 3 Algebra
10th Maths Exercise 3.5 Solution Chapter 3 Algebra Samacheer Kalvi


10th Maths Exercise 3.5 Question 4.
If x = a2+3a43a23 and y = a2+2a82a22a4 find the value of x2y2.
Solution:
Exercise 3.5 Class 10 Samacheer Kalvi Chapter 3 Algebra

Exercise 3.5 Class 10 Maths Samacheer Question 5.
If a polynomial p(x) = x2 – 5x – 14 is divided by another polynomial q(x) we get x7x+2 find q(x).
Solution:
p(x) = x2 – 5x – 14
10th Maths Exercise 3.5 3rd Sum Chapter 3 Algebra Samacheer Kalvi

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